Forked from kasimte/ConditionalStringOptionalUnwrapping.swift
Created
October 24, 2018 11:36
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An example of conditional String optional unwrapping in Swift 3.
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| var optional: String? = "Hello World" | |
| if let o = optional { // Same as: optional as String! | |
| print(o) | |
| } | |
| // Output: Hello World. | |
| if let o = optional as String! { | |
| print(o) | |
| } | |
| // Output: Hello World. | |
| var blankOptional: String? | |
| if let o = blankOptional { | |
| print(o) | |
| } | |
| // No output. | |
| if let o = optional as String { | |
| print(o) | |
| } | |
| // Error: String? is not convertible to String without force downcast. | |
| if let o = optional as? String { | |
| print(o) | |
| } | |
| // Warning: Conditional downcast from String? to String does nothing. |
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