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mdixon47/uniqueInOrder.js

Last active May 29, 2024 12:32
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Implement the function unique_in_order which takes as argument a sequence and returns a list of items without any elements with the same value next to each other and preserving the original order of elements.
Raw
uniqueInOrder.js
function uniqueInOrder(it) {
var result = []
var last
for (var i = 0; i < it.length; i++) {
if (it[i] !== last) {
result.push(last = it[i])
}
}
return result
}
@damianjnc
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damianjnc commented Mar 20, 2020

Hi, it should be something like that:

functionuniqueInOrder(iterable){
  //your code here - remember iterable can be a string or an array
  const result = []
  
  for(let i = 0; i < iterable.length; i++){
    if(iterable[i] !== iterable[i + 1]){
      result.push(iterable[i])
    }
  }
  
  return result
}

@Nyambura254
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Nyambura254 commented May 15, 2020

this is the right way

function uniqueInOrder(iterable){
//your code here - remember iterable can be a string or an array
const result = [ ]

for(let i = 0; i < iterable.length; i++){
if(iterable[ i ] !== iterable[i + 1]){
result.push(iterable[ i ])
}
}

return result
}

@christianwondeson
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christianwondeson commented Jul 9, 2022

thanks this helps

@ChrisKeith01
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ChrisKeith01 commented May 29, 2024

I'm very confused I tried both methods and my code failed both tests.

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