Created
January 14, 2016 03:17
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Eratosthenes 算法
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| #include <stdio.h> | |
| #include <stdlib.h> | |
| #define N 10000 | |
| int main() | |
| { | |
| int i, j, a[N]; | |
| for (i = 2; i < N; i++) a[i] = 1; | |
| for (i = 2; i < N; i++) | |
| { | |
| if (a[i]) | |
| for (j = i; j < N/i; j++) | |
| a[i*j] = 0; | |
| } | |
| for (i = 2; i < N; i++) | |
| if (a[i]) printf("%4d ", i); | |
| printf("\n"); | |
| return 0; | |
| } |
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