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August 18, 2012 10:13
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This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters. Learn more about bidirectional Unicode charactersOriginal file line number Diff line number Diff line change @@ -0,0 +1,91 @@ import java.util.*; public class simplesa { private final String[] suffixes; private final int N; private int[] sa,lcp,nofsubs,nofusubs,nofusubs_acc; public simplesa(String s) { N = s.length(); suffixes = new String[N]; sa = new int[N]; lcp = new int[N]; nofsubs = new int[N]; nofusubs = new int[N]; nofusubs_acc = new int[N]; for (int i = 0; i < N; i++) suffixes[i] = s.substring(i); Arrays.sort(suffixes); sa[0] = this.index(0); lcp[0] = 0; nofsubs[0] = N - sa[0]; nofusubs[0] = nofsubs[0]; nofusubs_acc[0] = nofsubs[0]; for (int i = 1; i < s.length(); i++) { sa[i] = this.index(i); lcp[i] = lcp(i); nofsubs[i] = N - sa[i]; nofusubs[i] = nofsubs[i] - lcp[i]; nofusubs_acc[i] = nofusubs_acc[i-1] + nofusubs[i]; } } // index of ith sorted suffix public int index(int i) { return N - suffixes[i].length(); } // length of longest common prefix of s and t private static int lcp(String s, String t) { int N = Math.min(s.length(), t.length()); for (int i = 0; i < N; i++) if (s.charAt(i) != t.charAt(i)) return i; return N; } // longest common prefix of suffixes(i) and suffixes(i-1) public int lcp(int i) { return lcp(suffixes[i], suffixes[i-1]); } public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); sc.nextLine(); StringBuilder sb = new StringBuilder(); while(n-- > 0){ sb.append(sc.nextLine()); } String generalized = sb.toString(); //String generalized = sc.nextLine(); simplesa suffix = new simplesa(generalized); for (int i = 0; i < generalized.length(); i++) { System.out.println(" "+i+" "+suffix.sa[i]+" "+suffix.lcp[i] +" "+suffix.nofsubs[i]+" "+suffix.nofusubs[i]+" "+suffix.nofusubs_acc[i] +" "+generalized.substring(suffix.sa[i])); } //binary search int l =8; int m=0, lo = 0, hi = generalized.length(); while(lo <= hi){ m = lo + (hi - lo)/2; if (suffix.nofusubs_acc[m] > l){ hi = m - 1; } else if (suffix.nofusubs_acc[m] < l){ lo = m + 1; } else { break; } } System.out.println(lo); if(lo -1 > 0){ System.out.println(generalized.substring(suffix.sa[lo], suffix.sa[lo]+suffix.lcp[lo]+l-suffix.nofusubs_acc[lo-1])); } else { System.out.println(generalized.substring(suffix.sa[lo], suffix.sa[lo]+suffix.lcp[lo]+l)); } } }