they changed the className, at least in Firefox 81, now should be:

for (let k of document.getElementsByClassName("qa-unregister-button")) k.click()

they changed the className, at least in Firefox 81, now should be:

for (let k of document.getElementsByClassName("qa-unregister-button")) k.click()

I've updated the code snippet. Thank you!

I had to update it to the following to work for me on FF 87.0

for (let k of document.querySelectorAll('[data-l10n-id="unregister-button"]')) k.click()

Thanks! This did it for me (FF 101.0b9, Developer Edition):

$$('.qa-unregister-button').forEach(b => b.click()) 

FF 143.0.3 (aarch64)

URL: about:serviceworkers

document.querySelectorAll('#serviceworkers>div button[data-l10n-id="unregister-button"]').forEach(btn=> btn.click() )

To quote an ancient UK advertisement for tea, this is the TAYST! 🪇 💃

FF 143.0.3 (aarch64)
URL: about:serviceworkers

document.querySelectorAll('#serviceworkers>div button[data-l10n-id="unregister-button"]').forEach(btn=> btn.click() )

It also works in 148.0.2 (64-bit) (mozilla-deb from

Here it is in bookmarklet form, if you want to make a button for it:

javascript:(function(){document.querySelectorAll('#serviceworkers>div button[data-l10n-id="unregister-button"]').forEach(btn=> btn.click() )})();

Just add a new bookmark and paste that into the URL field. 👍
Heck, you could probably add a couple of lines to open the page, then prompt you you OK the process. 😲