Created
October 22, 2013 02:00
-
-
Save yunlzheng/7094084 to your computer and use it in GitHub Desktop.
计算两个时间之间的间隔时间
This file contains hidden or bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
| # coding: utf-8 | |
| import datetime | |
| def timediffer(dt1, dt2): | |
| """ | |
| 计算两个时间点之间的时间差： | |
| 当时间差大于1秒，切小于一分钟时，返回dt1和dt2之间相差的秒数 | |
| 当时间差大于一分钟，且小宇一小时时，返回dt1和dt2之间相差的分钟数 | |
| 当时间差大于一小时并且小于一天时，返回dt1和dt2之间相差的小时数 | |
| 当时间差大于1天，且小于一个月时，dt1和dt2之间相差的天数 | |
| 当时间差大于一个月，且小于一年时，返回dt1和dt2之间相差的月数 | |
| @param dt1: datetime | |
| @param dt2: datetime | |
| """ | |
| dt = dt2 - dt1 | |
| print type(dt) | |
| microsecond = dt.microseconds #(>= 0 and less than 1 second) | |
| second = dt.seconds #>= 0 and less than 1 day | |
| if second is not 0: | |
| if second <60: | |
| print "大约在{0}秒前".format((second)) | |
| elif second >= 60 and second < 3600: | |
| print "大约在{0}分钟前".format(second/60) | |
| elif second>=3600: | |
| print "大约在{0}小时前".format(second/3600) | |
| day = dt.days | |
| print "{0} {1} {2} ".format(microsecond, second, day) | |
| return | |
| if __name__ == '__main__': | |
| dt1 = datetime.datetime.now() | |
| dt2 = dt1 + datetime.timedelta(hours=26) | |
| timediffer(dt1, dt2) |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment