$ printf %s 'encode this'|jq -sRr @uri
encode%20this
$ jq -rn --arg x 'encode this' '$x|@uri'
encode%20this
-r (--raw-output) outputs the raw contents of strings instead of JSON string literals. -n (--null-input) doesn't read input from STDIN.
-R (--raw-input) treats input lines as strings instead of parsing them as JSON, and -sR (--slurp --raw-input) reads the input into a single string. You can replace -sRr with -Rr if your input only contains a single line, or if you don't want to replace linefeeds with %0A:
$ printf %s\\n 'multiple lines' 'of text'|jq -Rr @uri
multiple%20lines
of%20text
$ printf %s\\n 'multiple lines' 'of text'|jq -sRr @uri
multiple%20lines%0Aof%20text%0A
Or this percent-encodes all bytes:
xxd -p|tr -d \\n|sed 's/../%&/g'
Last active
January 9, 2026 21:10
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Simply URL encode string with Linux/Bash/Shell tools
very handy!
Maybe a shorter version:
echo 'encode this' | jq -Rr @uri
Maybe a shorter version:
echo 'encode this' | jq -Rr @uri
Better use printf because echo appends a possibly unwanted \n at the end.
Normally I do this
echo -n 'encode this' | jq -Rr @uri
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Ti lovvo smodatamente.
Risolto in 30" una questione che pensavo mi richiedesse ore. (Solved in 30" a question that I thought would take me hours.)