seq 1 99999999999 | awk '{
  for(i=1;i<=11;i++){
    a=int($0/(10^(i-1)));
    b=a-int(a/10)*10;
    if(i<=6){
      sum+=b*(i+1)
    } else {
      sum+=b*(i-5)
    }
  };
  r=sum%11;
  if(r==0||r==1){
    cd=0
  }else{
    cd=11-r
  }
  printf "%011d\n", $0*10+cd
}'