Created
April 2, 2019 06:00
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Comparison between two solutions to hamming numbers in Haskell
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| module Hamming (ham1, ham2) where | |
| ham1 :: [Integer] | |
| ham1 = 1 : | |
| map (* 2) ham1 `merge` | |
| map (* 3) ham1 `merge` | |
| map (* 5) ham1 | |
| merge :: Ord a => [a] -> [a] -> [a] | |
| merge [] l = l | |
| merge l [] = l | |
| merge (x : xs) (y : ys) | x < y = x : merge xs (y : ys) | |
| | x == y = x : merge xs ys | |
| | otherwise = y : merge (x : xs) ys | |
| ham2 :: Integer -> [Integer] -> ([Integer], [Integer], [Integer]) -> [Integer] | |
| ham2 1 xs _ = xs | |
| ham2 n xs (q2, q3, q5) = ham2 (n - 1) (xs ++ [x]) update | |
| where | |
| x = minimum $ map head [q2, q3, q5] | |
| update | x == head q2 = ((tail q2) ++ [x * 2], q3 ++ [x * 3], q5 ++ [x * 5]) | |
| | x == head q3 = (q2, (tail q3) ++ [x * 3], q5 ++ [x * 5]) | |
| | otherwise = (q2, q3, (tail q5) ++ [x * 5]) |
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